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A data scientist uses hp.loguniform("learning_rate", np.log(1e-5), np.log(1e-1)) in a Hyperopt search space. What is the practical implication of using loguniform versus uniform for the learning rate?

AThe learning rate will only take values that are powers of 10
BSampling is uniform in log space, so the algorithm explores small and large learning rates with equal probability per order of magnitude
CThe learning rate is fixed at the geometric mean of the bounds
DOnly integer values within the range are sampled

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